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Three forces P, Q and R are acting on a ...

Three forces P, Q and R are acting on a particel in the plane, the angle between P and Q and that between Q and R are `150^(@)` and `120^(@)` respectively. Then for equilibrium, forces P, Q and R are in the ratio

A

`1:2:3`

B

`1:2:sqrt(3)`

C

`3:2:1`

D

`sqrt(3):2:1`

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The correct Answer is:
To solve the problem of finding the ratio of the forces P, Q, and R for equilibrium, we can use the concept of vector addition and the sine rule. Here’s a step-by-step solution: ### Step 1: Understand the Geometry of Forces We have three forces P, Q, and R acting on a particle. The angles between the forces are given as follows: - Angle between P and Q = 150° - Angle between Q and R = 120° ### Step 2: Set Up the Vector Diagram To analyze the forces, we can visualize them in a vector diagram. Place force P along the positive x-axis. Then, force Q will be at an angle of 150° from P, and force R will be at an angle of 120° from Q. ### Step 3: Use the Law of Sines In a triangle formed by the forces, we can apply the Law of Sines. The angles in the triangle can be calculated as follows: - The angle opposite to force P (let's call it α) can be calculated as: α = 180° - 150° - 120° = -90° (which means we have a reflex angle, so we will take it as 90° for our calculations). ### Step 4: Apply the Law of Sines According to the Law of Sines: \[ \frac{P}{\sin(120°)} = \frac{Q}{\sin(90°)} = \frac{R}{\sin(150°)} \] ### Step 5: Calculate the Ratios From the above relationships, we can express the forces in terms of a common ratio k: - \( P = k \cdot \sin(120°) \) - \( Q = k \cdot \sin(90°) \) - \( R = k \cdot \sin(150°) \) ### Step 6: Calculate the Sine Values Now we can calculate the sine values: - \( \sin(120°) = \frac{\sqrt{3}}{2} \) - \( \sin(90°) = 1 \) - \( \sin(150°) = \frac{1}{2} \) ### Step 7: Substitute the Values Substituting these values into the equations gives: - \( P = k \cdot \frac{\sqrt{3}}{2} \) - \( Q = k \cdot 1 \) - \( R = k \cdot \frac{1}{2} \) ### Step 8: Find the Ratio Now, we can find the ratio of P, Q, and R: \[ \frac{P}{Q} : \frac{Q}{Q} : \frac{R}{Q} = \frac{\frac{\sqrt{3}}{2}}{1} : 1 : \frac{\frac{1}{2}}{1} \] This simplifies to: \[ \frac{\sqrt{3}}{2} : 1 : \frac{1}{2} \] ### Step 9: Clear the Fractions To express this in a more standard form, we can multiply through by 2 to eliminate the fractions: \[ \sqrt{3} : 2 : 1 \] ### Final Answer Thus, the ratio of the forces P, Q, and R for equilibrium is: \[ \sqrt{3} : 2 : 1 \]

To solve the problem of finding the ratio of the forces P, Q, and R for equilibrium, we can use the concept of vector addition and the sine rule. Here’s a step-by-step solution: ### Step 1: Understand the Geometry of Forces We have three forces P, Q, and R acting on a particle. The angles between the forces are given as follows: - Angle between P and Q = 150° - Angle between Q and R = 120° ### Step 2: Set Up the Vector Diagram ...
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