A man can swim in still water with a speed of `2 ms^-1`. If he wants to cross a river of water current speed `sqrt(3) ms^-1` along the shortest possible path, then in which direction should he swim ?

Options

A. at an angle `120^(@)` to the water current
B. at an angle `150^(@)` to the water current
C. at an angle `90^(@)` to the water current
D. none of these

Answer

B

Explanation

`sin theta=(sqrt(3))/2 implies theta=60^(@)`
Hence `150^(@)` with water current.