Two particles P and Q are located at distance `r_(p) and r_(Q)` respectively form the centre of rotating disc such that `r_(P)gtr_(Q)`. The disc is rotating with constant angular acceleration. We can say

Options

A. both P and Q have the same acceleration
B. both P and Q do not have the same acceleration
C. P has greater acceleration than Q
D. Q has greater acceleration than P

Answer

c

Explanation

Resultant acceleration,
`a=sqrt(a_(r)^(2)+a_(t)^(2))=sqrt((omega^(2)r)^(2)+(r alpha)^(2))`
`implies a=rsqrt((omega^(2))^(2)+(alpha)^(2))`
As `omegan and alpha` will be same for both the particles P and Q, hence `a_(p)gta_(Q)( :. R_(P) gt r_(Q))`