A partical is moving along a circular path of radius `5m` and with uniform speed `5 m//s`. What will be the avarage acceleration when the partical completes half revoluation?

Options

A. zero
B. `10m//s^(2)`
C. `10pm//s^(2)`
D. `(10//pi)m//s^(2)`

Answer

d

Explanation

The change in velocity when the particle completes half revolution is given by
`Deltav=5m//s-(-5m//s)=10m//s`
Time taken to complete half revolution
`t=(pir)/v=(pixx5)/5=pi sec`
Average acceleration `=(Deltav)/t=10/pi m//s^(2)`