Moment of inertia of a uniform rod of length `L` and mass `M`, about an axis passing through `L//4` from one end and perpendicular to its length is

Options

A. `(Ml^2)/(48)`
B. `(ML^2)/(48)`
C. `(ML^2)/(12)`
D. `(7 ML^2)/(48)`

Answer

D

Explanation

(d) Apply parallel axis theorem
`I = I_(cm) + Mh^2 = (ML^2)/(12) + M ((L)/(4))^2 = (7 ML^2)/(48)`.