Two uniform identicla rods each of mass M and length l are joined to form a cross as shown in figure. Find the momet of inertia of the cross about a bisector as shown doted in the figure

Options

A. `(ML^2)/(6)`
B. `(ML^2)/(4)`
C. `(ML^2)/(12)`
D. `(ML^2)/(3)`

Answer

C

Explanation

( c) We have to find `I_1` ?
`I_1 = I_2`... (1)
`I_0 = (ML^2)/(12) + (ML^2)/(12) = (ML^2)/(6)`
now `I_1 + I_2 = I_0`…(2)
From (1) and (2), `I_1 = (I_0)/(2) = (ML^2)/(12)`
.