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Seven identical discs are arranged in a hexagonal, planar pattern so as to touch each neighbor, as shown in the figure. Each disc has mass `m` and radius `r`. What is the moment of inertia of the system of seven discs about an axis passing through the centre of central disc and normal to plane of all discs ?
.

A

`(7)/(2) mr^2`

B

`(13)/(2) mr^2`

C

`(29)/(2) mr^2`

D

`(55)/(2) mr^2`

Text Solution

Verified by Experts

The correct Answer is:
D

(d) `I = I_0 + 6 I'`
`I_0` is the moment of inertia of central disc and `I'` is moment of inertia of rest of the each disc about specified axis.
By parallel axes theorem
`I = (mr^2)/(2) + 6(I_(cm) + md^2) = (mr^2)/(2) + 6[(mr^2)/(2) + m(2 r)^2]`
=`(mr^2)/(2)+(6 mr^2)/(2)+ 24 mr^2 = (55 mr^2)/(2)`.
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