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The moment of inertia of a body about a ...

The moment of inertia of a body about a given axis is `1.2 kg m^(2)`. Initially, the body is at rest. In order to produce a rotational `KE` of `1500 J`, for how much duration, an acceleration of `25 rad s^(-2)` must be applied about that axis ?

A

4 s

B

2 s

C

8 s

D

10 s

Text Solution

Verified by Experts

The correct Answer is:
B

(b) `KE = (1)/(2) I omega^2 rArr KE = (1)/(2) I omega^2`
`rArr omega = 50 rad//s t= (omega)/(prop) = (50)/(25) = 2 s`.
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