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A body rolls without slipping. The radiu...

A body rolls without slipping. The radius of gyration of the body about an axis passing through its centre of mass is `K`. The radius of the body is `R`. The ratio of rotational kinetic energy to translational kinetic energy is.

A

`(K^2)/(R^2)`

B

`(R^2)/(K^2 + R^2)`

C

`(K^2)/(K^2 + R^2)`

D

`K^2 + R^2`

Text Solution

Verified by Experts

The correct Answer is:
A

(a) `(Rotational K.E.)/(Translational K.E.) = ((1)/(2) I omega^2)/(1/(2) mv)= (m K^2 (v^2)/(R^2))/(mv^2) = (K^2)/(R^2)`.
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