A rolling object rolls without slipping down an inclined plane (angle of inclination `theta`), then the minimum acceleration it can have is.
.

Options

A. `g sin theta`
B. `(2 g sin theta)/(3)`
C. `(g sin theta)/(2)`
D. zero

Answer

C

Explanation

( c) `a = (g sin theta)/(1 + (I)/(MR^2))`
`a` is minimum, if `I` is maximum.
`I_(max) = MR^2` [for ring]
`rArr a_(min) = (g sin theta)/(1 + (MR^2)/(MR^2))=(g sin theta)/(2)`.