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A satellite with kinetic energy E(k) is ...

A satellite with kinetic energy `E_(k)` is revolving round the earth in a circular orbit. How much more kinetic energy should be given to it so that it may just escape into outer space

A

`E_(k)`

B

`2E_(k)`

C

`1/2E_(k)`

D

`3E_(k)`

Text Solution

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The correct Answer is:
To solve the problem of how much more kinetic energy should be given to a satellite so that it may just escape into outer space, we can follow these steps: ### Step 1: Understand the total mechanical energy of the satellite in orbit The total mechanical energy \( E \) of a satellite in a circular orbit is given by the formula: \[ E = K + U \] where \( K \) is the kinetic energy and \( U \) is the gravitational potential energy. For a satellite in a circular orbit, the gravitational potential energy \( U \) is given by: \[ U = -\frac{G M m}{r} \] and the kinetic energy \( K \) is: \[ K = \frac{1}{2} m v^2 \] where \( G \) is the gravitational constant, \( M \) is the mass of the Earth, \( m \) is the mass of the satellite, and \( r \) is the distance from the center of the Earth to the satellite. ### Step 2: Relate kinetic energy and potential energy In a stable circular orbit, the kinetic energy is related to the potential energy by: \[ K = -\frac{1}{2} U \] Thus, the total energy can be expressed as: \[ E = K + U = K - 2K = -K \] So, the total energy \( E \) of the satellite is: \[ E = -\frac{G M m}{2r} \] ### Step 3: Determine the energy required to escape To escape from the gravitational influence of the Earth, the satellite must have a total energy of zero. Therefore, the energy required to escape \( \Delta E \) can be calculated as: \[ \Delta E = 0 - E = 0 - \left(-\frac{G M m}{2r}\right) = \frac{G M m}{2r} \] ### Step 4: Calculate the additional kinetic energy needed Let the current kinetic energy of the satellite be \( E_k \). The additional kinetic energy \( \Delta K \) needed to reach the escape energy is: \[ \Delta K = \Delta E - E_k \] Substituting for \( \Delta E \): \[ \Delta K = \frac{G M m}{2r} - E_k \] ### Conclusion Thus, the additional kinetic energy that should be given to the satellite so that it may just escape into outer space is: \[ \Delta K = \frac{G M m}{2r} - E_k \]

To solve the problem of how much more kinetic energy should be given to a satellite so that it may just escape into outer space, we can follow these steps: ### Step 1: Understand the total mechanical energy of the satellite in orbit The total mechanical energy \( E \) of a satellite in a circular orbit is given by the formula: \[ E = K + U \] where \( K \) is the kinetic energy and \( U \) is the gravitational potential energy. ...
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