The maximum acceleration of a particle in `SHM` is motion two lines keeping the maximum speed in the constant it is position when

Options

A. amplitude of oscilation while frequency remain constant
B. amplatude is doubled while frequency is halved
C. amplatude is doubled while frequency is halved
D. frequency is doubled while amplitude remain constant.

Answer

C

Explanation

`2A_(i) omega_(i)^(2) = A_(f) omega_(f)^(2)`
` A_(i) omega_(i)= A_(f) omega_(f)`
If `omega_(f) = 2omega_(i)` and `A_(f) = (A_i)/(2)`
The condition will be satisfied.