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A particle is vibrating simple harmonica...

A particle is vibrating simple harmonically with amplitude `'a'`. The displacement of the particle when its energy is half kinetic and half potential is.

A

`a//2`

B

`a//sqrt(2)`

C

`a//4`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B

Kinetic energy `=` Potential energy
`(1)/(2) m omega^(2) (a^(2) - y^(2)) = (1)/(2) m omega^(2) y^(2)`
`a^(2) - y^(2) = y^(2)`
`2y^(2) = a^(2) rArr y = +- (a)/(sqrt(2))`
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