An object of mass `0.2 kg` executes simple harmonic oscillation along the `x` - axis with a frequency of `(25//pi) Hz`. At the position `x = 0.04`, the object has Kinetic energy of `0.5 J` and potential energy 0.4 J. The amplitude of oscillations (in m) is

Options

A. `0.05`
B. `0.06`
C. `0.01`
D. None of these

Answer

B

Explanation

`E = (1)/(2) m omega^(2) A^(2) rArr E = (1)/(2) m (2 pi f)^(2) A^(2)`
`rArr A = (1)/(2pi f) sqrt((2E)/(m)`
Putting values we obtain ,
`A = (1)/(2pi((25)/(pi))) sqrt((2 xx (0.5 + 0.4))/(0.2)) rArr A = 0.06 m`