A body executes simple harmonic motion. The potential energy (P.E), the kinetic energy (K.E) and energy (T.E) are measured as a function of displacement `x`. Which of the following staements is true?

Options

A. `TE` is zero when `x= 0`
B. `PE` is maximum when `x= 0`
C. `KE` is maximum when `x= 0`
D. `KE` is maximum when `x` is maximum

Answer

C

Explanation

`PE = (1)/(2) m omega^(2) y^(2)`
`KE= (1)/(2) m omega^(2)(a^(2) - y^(2))`
`TE = PE + KE`
`= (1)/(2) m omega^(2) a^(2)`
Since `PE` is maximum at `x = a` and `KE` is maximum at `x = 0` therefore `TE` remain constant throughout the motion.