The frequency of oscilation is `((10)/(pi))` (in Hz) of a particle of mass `0.1 kg` which executes `SHM` is `0.2J` at position `x = 0.02m`. The potential energy is zero at mean position Find the amplitude of osclllation (in meter)`:

Options

A. `(1)/(2sqrt(10)`
B. `(1)/(sqrt(10)`
C. `sqrt(10)`
D. `2sqrt(10)`

Answer

A

Explanation

`omega = 2pi f = ((K)/(m))^(1//2)`
`K = (2pi f)^(2) m`
`(1)/(2) KA^(2) =` total energy of oscillation `= 0.5 J`
`A = sqrt((1.0)/(K)) = (1)/(23 pi f ) sqrt((1.0)/(0.1)) = (1)/(2sqrt(10))`