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The displacement of a particle varies ac...

The displacement of a particle varies according to the relation `y = 4(cos pi t + sin pi t)`. The amplitude of the particle is

A

g

B

`-4`

C

`4`

D

`4 sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`x = 4(cos pi t + sin pi t)`
`= 4 sqrt(2) [(1)/(sqrt(2)) cos pi t + (1)/(sqrt(2)) sin pi t]`
`= 4 sqrt(2) [sin(pi)/(4) cos pi t + cos (pi)/(4)sin pi t]`
`4 sqrt(2) sin (pi t + (pi)/(4))`
Standard equation of displacement is
`x = a sin ( omega t + phi)`
Comparing the given equation with standerd equation
`a = 4 sqrt(2)`
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