The potential energy of a harmonic oscillation when is half way to its and end point is (where `E` it’s the total energy)

Options

A. `(1)/(8)E`
B. `(1)/(4)E`
C. `(1)/(2)E`
D. `(2)/(3)E`

Answer

B

Explanation

`(U)/(g) = ((1)/(2)m omega^(2)y^(2))/((1)/(2) m omega^(2)a^(2)) = (y^(2))/(a^(2)) = (((a)/(2))^(2))/(a^(2)) = (1)/(4) rArr U = (E )/(4)`