The particle executing simple harmonic motion has a kinetic energy `K_(0) cos^(2) omega t`. The maximum values of the potential energy and the energy are respectively

Options

A. `0 and 2K_(0)`
B. `(K_(0))/(2) and K_(0)`
C. `K_(0) and 2K_(0)`
D. `K_(0) and K_(0)`

Answer

D

Explanation

In simple harmonic motion the total energy of the particle is constant at all instants which is totelly kinetic when oparticle its passing through the mean position and is totally potential when particle is passing through the extent position
The verticllly of `PE` and `KE` with time a should in the figure its dotted parabloms curve and solud posiblity curve respectively
R Figure indecates that maximum value of total enerfgy `KE` and `PE` at `SHM` are equal M
`E_(g) = k_(0) cos^(2) omega t`
`(E_(g))/(E_(max)) = k_(0)`
so `(E_(g)) _(max) = k_(0)` and `(E)_(net) = k_(0)`