Two pearticle are oscillation along two close parallel straght lines side by side with the same frequency and amplitude They pass each other moving in opposite directions when their displacement is half of the on a stright line perpendicular to the part of the two particle The phase difference is

Options

A. zero
B. `(2pi)/(5)`
C. `pi`
D. `(pi)/(6)`

Answer

B

Explanation

Equation of `SHM` is given by
`x = A sin (omega t + delta)`
`(omega t = delta)` is called phase.
When `x = (A)/(2)` then
`sin (omega t + delta) = (1)/(2) implies omega t + delta = (pi)/(6)`
or `phi_(1) = (pi)/(6)`
For second particle, `phi_(2) = pi - (pi)/(6) = (5 pi)/(6)`
`:. phi = phi_(2) = phi_(1)`
`= (4pi)/(6) = (2 pi)/(3)`