A simple pendulum hangs the celling of a car if the car acceleration with a uniform acceleration , the frequency of the simple pendulum will

Options

A. increase
B. decrease
C. become infinite
D. remain constrant

Answer

A

Explanation

In this case frequency of oscillation is given by
`n = (1)/(2pi) sqrt(sqrt(g^(2) +a^(2))/(l))` where a is the acceleration of car if a increase then `n` also increase