Two bodies `P` and `Q` of equal masses are suspended from two separate massless springs of force constants `k_(1)` and `k_(2)` respectively. If the two bodies oscillate vertically such that their maximum velocities are equal. The ratio of the amplitude of `P` to that of `Q` is

Options

A. `(k_(1))/(K_(2))`
B. `sqrt((k_(1))/(K_(2)))`
C. `(k_(2))/(K_(1))`
D. `sqrt((k_(2))/(K_(1)))`

Answer

D

Explanation

Maximum velocity ` = omega t = asqrt((k)/(m))`
Given that `a sqrt((k_(1))/(m) = a_(1) sqrt((k_(2))/(m)) rArr (a_(1))/(a_(2)) = sqrt((k_(2))/(k_(1))`