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A spring of Force- constant K is cut int...

A spring of Force- constant `K` is cut into two pieces sach that one piece is double the length of the other . Then the long pieces will have a force - constant of

A

`(2//3)k`

B

`(3//2)k`

C

`3k`

D

`6k`

Text Solution

Verified by Experts

The correct Answer is:
B

Force constant `(k) prop (1)/("Length of spring")`
`(K)/(K_(1)) = (l_(1))/(l) = ((2)/(3)t)/(l)rArr K_(1) - (3)/(2)K`
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