At t=0,a transverse wave pulse travelling in the positive x direction with a speed of `2 m//s` in a wire is described by the function `y=6//x^(2)` given that `x!=0`. Transverse velocity of a particle at x=2 m and t= 2 s is

Options

A. `3m//s`
B. `-3m//s`
C. `8m//s`
D. `-8m//s`

Answer

B

Explanation

`y(xt=0)=(6)/(x^2)` then `y(xt)=(6)/((x-2t)^2)`
`implies(del y)/(del t)=(24)/((x-2t)^3)` at `x=2`,`t=2`
`V_Y=(24)/((-2)^3)=-3 m//s`