The equation `y=A cos^(2) (2pi nt -2 pi (x)/(lambda))` represents a wave with

Options

A. Amplitude `A//2`, frequency `2n` and wavelength `(lamda)/(2)`
B. Amplitude `A//2` frequency `2 n` and wavelength `lamda`
C. Amplitude ` A` , frequency ` 2 n` and wavelength `2lamda`
D. Amplitude ` A` , frequency `n` and wavelength `lambda`

Answer

A

Explanation

The given equation can be x written as
`y=(A)/(2)cos(4pint-(4pix)/(lamda))+(A)/(2)`
`(`:.` Cos^(2) theta =(t +cos 2 theta)/(2))`
Hence amplitude`=(A)/(2)` and frequency `=(omega)/(2pi)=(4pin)/(2pi)`
`=2n` and wave length `=(2pi)/(k)=(2pi)/((4pi)/(lamda))=(lamda)/(2)`