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If the speed of the wave shown in the fi...


If the speed of the wave shown in the figure is `330m//s` in the given medium then the equation of the wave propagating in the positive x-direction will be (all quantities are in M.K.S units)

A

`y=0.05sin2pi(4000t-12.5x)`

B

`y=0.05sin2pi(4000t-122.5x)`

C

`y=0.05sin2pi(3300t-10x)`

D

`y=0.05sin2pi(3300x-10t)`

Text Solution

Verified by Experts

The correct Answer is:
C
Here `A=0.05m`,`(5lamda)/(2)=0.025implieslamda=0.1m`
Now standard equation of wave
`y=Asin(2pi)/(lamda)(vt-x)impliesy=0.5sin2pi(3300t-10x)`
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