Water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap, the instant the first drop touches the ground. How far above the ground is the second drop at that instant. `(g = 10 ms^-2)`

Options

A. (a) ` 1 . 25 m`
B. (b) ` 2. 50 m`
C. (c ) ` 3. 75 m`
D. (d) ` 6 sec`

Answer

C

Explanation

Time taken by one drop to fall through ` 5 m` is
` sqrt 9 2S)/g ` = sqrt (2 xx 50/(10) = 1 sec`
:. Time interval for successive two drops is 91//20 sceond. The distance travelled by falling drop
` in (1//2) second is , ` S = 1/2 xx 10 x 91/2)^2 = 1.25 m`
:. Height of second drop from ground
` -= 5 - 1.25 m`.