For a particle in uniform circular motion , the acceleration ` vec(a)` at a point ` p ( R, theta )` on the circle of radiu ` R` is ( Here ` theta` is measured from the ` x- axis` )

Answer

B

Explanation

Refer Fig. 2 (CF). 70, centripetal acceleration of particle at (P)
.
` a_c = v^2 /R ` along ` PO`
As ` veca_c = vec a_x + vec a_y`
where, `_x =a-c cos theta = v^2/R cos theta`
` and ` a_y =a_c sin theta =v^2/R sin theta`
:. ` veca_c =a_x (- hati) +a_y (-hat j)`
`=- v^2/R cos theta hat i- v^2/R sin theta hat j`.