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At radioactive equillibrium, the ratio b...

At radioactive equillibrium, the ratio between two atoms of radioactive element `X` and `Y` are `3.1xx10^(9):1`, If half life period of `X` is `2.17xx10^(10)` years. Find half life of `Y`.

Text Solution

Verified by Experts

The correct Answer is:
`7`
At radioactive equilibrium, `X rarr Y`
`(N_(X))/(N_(Y)) = (lambda_(Y))/(lambda_(X)) = (t_(1//2x))/(t_(1//2Y))`
`:. (3.1xx10^(9))/(1) = (2.17xx10^(10))/(t_(1)//2Y)`
`:. T_(1//2Y) = 7.0` years
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