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The half-life of a radioactive isotope i...

The half-life of a radioactive isotope is 3 hour. IF the initial mass of isotope were `256g` the mass of it remaining undercayed after `18hr` is:

Text Solution

Verified by Experts

The correct Answer is:
`4`
`:' N = N_(0) ((1)/(2))^(n)`
`n = (18)/(3) = 6` (where `n` is no. of half-life)
`:. N = 256((1)/(2))^(6)`
`= 4g`
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