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One gram of .(79)Au^(198) (t(1//2) = 65h...

One gram of `._(79)Au^(198) (t_(1//2) = 65hr)` decays by `beta-` emission to produce stable `Hg`.
(a) Write nuclear reaction for process.
(b) How much `Hg` will be present after `260 hr`?

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The correct Answer is:
9b) `15//16g Hg`
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