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25 mL of H(2)O(2) solution were added t...

`25 mL ` of `H_(2)O_(2)` solution were added to excess of acidified solution of `KI`. The iodine so liberated required `20 mL` of `0.1N Na_(2)S_(2)O_(3)` for titration Calculate the strength of `H_(2)O_(2)` in terms of normalility, percentage and volumes.
(b) To a `25 mL H_(2)O_(2)` solution, excess of acidified solution of `KI` was added. The iodine liberated required `20 mL` of `0.3N` sodium thiosulphate solution. Calculate the volume strength of `H_(2)O_(2)` solution.

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To solve the problem step by step, we will break down the calculations for both parts of the question regarding the strength of the `H₂O₂` solution. ### Part (a) 1. **Understanding the Reaction**: - When `H₂O₂` reacts with `KI`, it liberates iodine (`I₂`). The reaction can be summarized as: \[ H_2O_2 + 2KI \rightarrow 2K^+ + I_2 + 2H_2O ...
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To a 25 mL H_(2)O_(2) solution excess of an acidified solution of potassium iodide was added. The iodine liberated required 20 " mL of " 0.3 N sodium thiosulphate solution Calculate the volume strength of H_(2)O_(2) solution.

To a 25 mL H_2 O_2 solution, excess of acidified solution of KI was added. The iodine liberated required 20.0 mL of 0.3 N Na_2 S_2 O_3 solution. Calculate the volume strength of H_2 O_2 solution.

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