The equivalent weight of `KMnO_(4)` in (a) neutral medium, (b) acidic medium and (c ) alkaline medium is `M//..` ( where `M` is mol.wt. of `KMnO_(4)`)

Answer

(a) 3 , (b) 5 , (c ) 1

Explanation

`Mn^(7+)+3e rarr Mn^(4+)` ( Neutral medium)
`:.` Eq.wt. `= M//3` ( Where `M` is mol.wt. of `KMnO_(4)`)
(b) `Mn^(7+)+5e rarr Mn^(2+)` ( Acidic medium)
(c ) `Mn^(7+)+1e rarr Mn^(6+)` ( Alkaline medium)
`:.` Eq.wt. `M//1`