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One mole of N(2)H(4) loses ten moles of ...

One mole of `N_(2)H_(4)` loses ten moles of electrons to form a new compound `A`. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in `A`? (There is no change in the oxidation state of hydrogen.)

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Verified by Experts

The correct Answer is:
3
`N_(2)H_(4)rarr(X)+10e`
`because X` contains all `N`-atoms
`:. (N^(2-))_(2)rarr(2N)^(a)+10e`
Therefore `2a-(-4)=10 rArr a=+3`
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