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The heat of atomisation of PH(3) is 228 ...

The heat of atomisation of `PH_(3)` is 228 K cal/mol and that os `P_(2)H_(4)` is `335` kCal/mol. The energy of `P-P` is (in kcal)

Text Solution

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`PH_(3(g))rarr P_((g))+3H_((g)), DeltaH=228kcal//mol`
`H_(2)P=PH_(2)rarr 2P_((g))+4H_((g)),DeltaH=355kcal//mol`
`:. DeltaH=e_(P-P)+4e_(P-H)`
or `355-e_(P-P)+4xx(228)/(3)( :. e_(P-H)=(228)/(3))`
`:. e_(P-P)=51kcal//mol`
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