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In DeltaABC,angleACB=90^(@) seg CD b...

In `DeltaABC,angleACB=90^(@)`
seg CD `bot` seg AB
seg DE `bot` seg CB.
Show that: `CD^(2)xxAC=ADxxABxxDE`

Text Solution

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The correct Answer is:
`:.CD^(2)xxAC=ADxxABxxDE`
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