Solve the following quadratic equations by using formula method :
`3m^(2)+2m-7=0`

Answer

`:.x=(-1pmsqrt22)/(3),(-1-sqrt22)/(3)` are the roots of the given quadratic equation.

Explanation

`3m^(2)+2m-7=0`
Comparing with the standard form
`ax^(2)+bx+c=0`
`a=3,b=2,c=-7`.
`b^(2)-4ac=(2)^(2)-4(3)(-7)=4+84=88`
`x=(-bpmsqrt(b^(2)-4ac))/(2a)=(-2pmsqrt88)/(2xx3)`
`=(-2pmsqrt(4xx22))/(6)=(-2pm2sqrt22)/(6)`
`=(-1pmsqrt(22))/(3)`
`:.x=(-1pmsqrt22)/(3)orx=(-1-sqrt22)/(3)`