With the help of the flow chart given below solve the equation `x^(2)+2sqrt(3)x+3=0` using formula.

Answer

`-sqrt3,-sqrt3` are the roots of the given quadratic equation.

Explanation

Step 1 : Comparing `x^(2)+2sqrt3x+3=0` with `ax^(2)+bx+c=0,a=1,b=2sqrt3,c=3.`
Step 2 : `b^(2)-4ac=(2sqrt3)^(2)-4(1)(3)=12-12=0`
Step 3 : `x=(-bpmsqrt(b^(2)-4ac))/(2a)" "......` (Formula)
Stpe 4 : `x=(-2sqrt3pmsqrt0)/(2xx1)=(-2sqrt3)/(2)=-sqrt3`
Here, the value of `b^(2)-4ac=0`.
`:.` the roots are real and equal