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Find the value of discriminant. 2y^(2)...

Find the value of discriminant.
`2y^(2)-5y+10=0`

Text Solution

Verified by Experts

The correct Answer is:
`Delta=-55`
Comparing `2y^(2)-5y+10=0` with the standard form `ax^(2)+bx+c=0,a=2,b=-5,c=10`
`Delta=b^(2)-4ac=(-5)^(2)-4(2)(10)`
`=25-80=-55`
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