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Find the values of the discriminant for ...

Find the values of the discriminant for the following equadratic equations :
`sqrt2x^(2)+4x+2sqrt2=0`

Text Solution

Verified by Experts

The correct Answer is:
`Delta=0`
Comparing `sqrt2x^(2)+4x+2sqrt2=0` with `ax^(2)+bx+c=0`,
`a=sqrt2, b=4,c=2sqrt2`
`Delta=b^(2)-4ac=(4)^(2)-4(sqrt2)(2sqrt2)`
`=16-16=0`
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