Solve the following quadratic equations :
`1/(x+5)=1/x^(2)`

Answer

`x=(1+sqrt21)/(2),(1-sqrt21)/(2)` are the roots of the given quadratic equation.

Explanation

`(1)/(x+5)=(1)/(x^(2))`
`:.x^(2)=x+5" "` …. (Cross multiplication)
`:.x^(2)-x-5=0`
Comparing it with `ax^(2)+bx+c=0`.
a=1, b=-1, c=-5
`b^(2)-4ac=(-1)^(2)-4(1)(-5)`
`=1+20=21`
`x=(-bpmsqrt(b^(2)-4ac))/(2a)`
`=(-(-1)pmsqrt21)/(2xx1)`
`=(1pmsqrt21)/(2)`
`:.x=(1+sqrt21)/(2)orx=(1-sqrt21)/(2)`