Solve the following quadratic equations :
`m^(2)+5m+5=0`

Answer

`x(-5+sqrt5)/(2),(-5-sqrt5)/(2)` are the roots of the given quadratic equation.

Explanation

`m^(2)+5m+5=0`
Comparing it with the standard form `ax^(2)+bx+c=0,a=1,b=5,=c=5`
`b^(2)-4ac=(5)^(2)-4(1)(5)`
=25-20=5
`x=(-bpmsqrt(b^(2)-4ac))/(2a)`
`=(-5pmsqrt5)/(2xx1)`
`=(-5pmsqrt5)/(2)`
`:.x(-5+sqrt5)/(2)orx=(-5-sqrt5)/(2)`