An alpha-particle is accelerated through...

An `alpha`-particle is accelerated through a.p.d of `10^(6)` volt the `K.E.` of particle will be

`1 Me V`

`2 Me V`

`4 Me V`

`8 Me V`

Text Solution

Verified by Experts

The correct Answer is:

`K = qV = 2e xx 10^(6) J = (2e xx 10^(6))/(e) eV = 2MeV`

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