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When a proton is accelerated through 1 V...

When a proton is accelerated through `1 V`, then its kinetic energy will be

A

`1840 eV`

B

`13.6 eV`

C

`1 eV`

D

`0.54 eV`

Text Solution

Verified by Experts

The correct Answer is:
C
`Delta KE = qV = eV = e xx 1 xx 1eV`
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