The distance between the plates of a parallel plate condenser is `4mm` and potential difference is `60` volts. If the distance between the plates is increased to `12mm`, then

Options

A. The potential difference of the condenser will become `180` volts
B. The potential difference will become `20` volts
C. The potential difference will remain unchanged
D. The charge on condenser will reduce to one third

Answer

A

Explanation

For capacitor
`(V_(1))/(V_(2)) = (d_(1))/(d_(2)) rArr V_(2) = (V_(1) xx d_(2))/(d_(1)) = (60 xx 12)/(4) = 180 V`