On increasing the plate separation of a charged condenser, the energy

Options

A. increases
B. decreases
C. remains unchanged
D. becomes zero

Answer

A

Explanation

Energy `U = (1)/(2)(Q^(2))/(C )` for a charged capacitor charge `Q` is constant and with the increase in separation `C` will decrease `(C prop (1)/(d))`, So overall `U` will increase.