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The capacitor of capacitance 4 muF and 6...

The capacitor of capacitance `4 muF` and `6 muF` are connected in series. A potential difference of `500` volts applied to the outer plates of the two capacitor system. Then the charge on each capacitor is numerically

A

`6000 C`

B

`1200 C`

C

`1200 muC`

D

`6000 muC`

Text Solution

Verified by Experts

The correct Answer is:
C
`C_(eq) = (C_(1)C_(2))/(C_(1) + C_(2)) = 2.4 muF`.
Charge flown `= 2.4 xx 500 xx 10^(-6) C = 1200 muC`.
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