`n` identical condenser are joined in parallel and are charged to potential `V`. Now they are separated and joined in series. Then the total energy and potential difference of the combination will be

Options

A. Energy and potential difference remain same
B. Energy remains same the potential differnece is `nV`
C. Energy increases times and potential difference is `nV`
D. Energy increases `b` times and potential difference remains same

Answer

B

Explanation

According to energy conservation, energy remains the same
`rArr U_("parallel") = U_(series) rArr (1)/(2) (nC)V^(2) = (1)/(2) ((C )/(n))v'^(2)`
`rArr V' = nV`
(`V' =` potential difference across series combiantion)