Two condensers of capacity `0.3 muF` and `0.6muF` respectively are connected in series. The combination is connected across a potential of `6` volts. The ratio of energies stored by the condensers will be

Options

A. `1//2`
B. `2`
C. `1//4`
D. `4`

Answer

B

Explanation

In series combination `Q` is constant, hence according to
`U = (Q^(2))/(2C) rArr U prop (1)/(C ) rArr (U_(1))/(U_(2)) = (C_(2))/(C_(1)) = (0.6)/(0.3) = (2)/(1)`