A condenser of capacitance `10 muF` has been charged to `100V`. It is now connected to another uncharged condenser in parallel. The common potential becomes `40 V`. The capacitance of another condenser is

Options

A. `15 muF`
B. `5 muF`
C. `10 muF`
D. `16.6 muF`

Answer

A

Explanation

By using `V = (C_(1)V_(1) + C_(2)V_(2))/(C_(1) + C_(2))`
`rArr 40 = (10 xx 100 + C_(2) xx 0)/(10 + C_(2)) rArr C_(2) = 15 muF`